Riddle Me This?Follow

I'll accept that... there was an icecicle that built up on the window. He stabbed himself and bleed to death. Ice melted. :). G/J.

Pardon the bump, but. . . .

As I was going to St. Ives I met a man with seven wives,
Each wife had seven sacks, each sack had seven cats,
Each cat had seven kits: kits, cats, sacks and wives,
How many were going to St. Ives?

days of the week are capitolized anyway

Ask either man, "Which way will the other man tell me to go?"
There is a RP (right path) and WP (wrong path).
If you ask the liar, then the other man is the honest man and will tell you the RP. But, because you asked the liar, you'll be told the WP.
If you ask the honest man, the other man is the liar and will tell you the WP. Because he's the honest man, he will tell you the WP.
Either way, whichever answer you get is the WP. You take the other route.
It's a simple logical function: (FALSE & TRUE) = FALSE in any permutation.

(Never type while multislacking)


Edited, Wed Jun 2 17:38:18 2004 by kahlyn

You have the logic a bit twisted on the 3 men in the hotel room. You can't take away the 2 bucks from the 27 because it makes no logical sence from the perspective of the 3 men.

Lets say you where one of the 3 men. The bell boy just arrived at your door and hands you 3 bucks. He says the front desk over charged you. So naturaly you give a buck to the other 2 and keep one for yourself. This means that out of your pocket you paid 9 dollars, and so did the other 2 gentlemen. That would equal 27. Thus you would think that the Hotel's room charge was 27 bucks. And then later if you found out the bell boy took 2 bucks you would then wonder where the other dollar was.

However the complete answer to this is not in taking 2 dollars out of the 27 because that is a trick of math, and will never add up right when you think harder about it. You must take the 27 bucks the guys paid and subtract the actual price of the room. There you will find the 2 bucks the bellboy took.

Corn.


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